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Bingel [31]
2 years ago
11

What is fundamental quantity?​

Physics
2 answers:
seraphim [82]2 years ago
5 0

Answer:

The Fundamental Quantity is independent Physical Quantity that is not possible to express in other Physical Quanitity. ... In Physics, Length, Mass, Time, Electric Current, Thermodynamic Temperature, etc are examples of Fundamental Quantities.

FrozenT [24]2 years ago
4 0

Explanation:

Fundamental quantities are mass, time, current, length, temperature, amount of substance and luminous intensity. All other physical quantities are derived quantities and can be made from fundamental quantities. Momentum is the product of mass and velocity.

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A block of wood is floating in water; it is depressed slightly and then released to oscillate up and down. Assume that the top a
Marysya12 [62]

Explanation:

Equilibrium position in y direction:

W = Fb (Weight of the block is equal to buoyant force)

m*g = V*p*g

V under water = A*h

hence,

m = A*h*p

Using Newton 2nd Law

-m*\frac{d^2y}{dt^2} = Fb - W\\\\-m*\frac{d^2y}{dt^2} = p*g*(h+y)*A - A*h*p*g\\\\-A*h*p*\frac{d^2y}{dt^2} = y *p*A*g\\\\\frac{d^2y}{dt^2} + \frac{g}{h} * y =0

Hence, T time period

T = 2*pi*sqrt ( h / g )

4 0
3 years ago
PLEASE HELP!! 13 POINTS! SCIENCE!
pogonyaev

Answer:

A.

Explanation:

3 0
3 years ago
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What happens to the force between two charges if one of the charges are doubled?
Julli [10]

Answer:

The new force between the charges becomes double of the initial force.

Explanation:

The force acting between charge particles is given by :

F=k\dfrac{q_1q_2}{r^2}

k is electrostatic constant

r is distance between charges

If one of the charges are doubled, then, q₁ = 2q₁

The new force becomes,

F'=\dfrac{2kq_1q_2}{r^2}\\\\F'=2F

So, the new force between the charges becomes double of the initial force.

7 0
3 years ago
A 2.30-kg cylindrical rod of length 2.00 m is suspended from a horizontal bar so it is free to swing about that end. a solid sph
Marina86 [1]

Solution:


initial sphere mvr = final sphere mvr + Iω 
where I = mL²/3 = 2.3g * (2m)² / 3 = 3.07 kg·m² 
0.25kg * (12.5 + 9.5)m/s * (4/5)2m = 3.07 kg·m² * ω 
where: ω = 2.87 rad/s 

So for the rod, initial E = KE = ½Iω² = ½ * 3.07kg·m² * (2.87rad/s)² 
E = 12.64 J becomes PE = mgh, so 
12.64 J = 2.3 kg * 9.8m/s² * h 
h = 0.29 m 

h = L(1 - cosΘ) → where here L is the distance to the CM 
0.03m = 1m(1 - cosΘ) = 1m - 1m*cosΘ 
Θ = arccos((1-0.29)/1) = 44.77 º 

8 0
3 years ago
What percentage of energy is available to organisms at each level of an energy pyramid?
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The percentage of energy available to each organism is always 10 percent . 
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