Answer:
The speed in of the plane is 115.47 m/sec
Step-by-step explanation:
Given:
Height at which the plane is flying = 6000 m
Angle of elevation at the radar base = 30 Degrees
Angle of elevation at the radar base after one minute = 60 Degrees
To Find:
The Speed of the plane in meter per second = ?
Solution:
Let us use the tangent of the angle to find the distance (d) to a point directly below plane:
<u>when the angle is 30 degrees</u>
d1 = 10392.3 meters
<u>when the angle is 60 degrees</u>
d2 = 3464.1 meters
<u>distance travelled by aircraft in 1 min is </u>
=>d1 - d2
=>0392.3 - 3464.1
= 6928.2 m/min
<u>Now converting to m/sec</u>
=>
=>115.47 m/sec
Answer:
Time required by Ben was 12 minutes.
Step-by-step explanation:
Given:
Time Required for Fred = 16 mins
Ben completed his run in 3/4 of the amount of time of Freds run.
We need to find the time required by Ben.
Now Given that;
Ben completed his run in 3/4 of the amount of time of Freds run.
It means that time required by Ben is equal to 3/4 times time required by Fred.
Time required by Ben = 
Time required by Ben = 
Hence Time required by Ben was 12 minutes.
The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.
Since the plane passes through point (-5,9,10), the required plane is :
Π 1(x-(-5)+4(y-9)-3(z-10)=0
=>
Π x+4y-3z=1
Answer
1/4 × 6 × (5a) = 12
15a=12
a= 4/5
Step-by-step explanation:
