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4 years ago

Find the range of the relation.

Mathematics

1 answer:

Vinil7 [7]4 years ago

3 0

Answer:

Range: (4,2,0,-2,-4)

Step-by-step explanation:

All the x values are domain.

All the v values are range.

(x,y) so the second number in the parenthesis is the range and the first one is the domain.

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Give the equation of the circle centered at the origin and passing through the point(0,10)

beks73 [17]

Answer:

$x^{2} + y^{2} = 100$

Step-by-step explanation:

The equation of a circle has the following format:

$(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}$

In which r is the radius(half the diameter) and the centre is the point $(x_{0}, y_{0})$

Centered at the origin

This means that $x_{0} = 0, y_{0} = 0$

Passing through the point(0,10)

The radius is the distance of any point in which the circle passes to the centre.

Using the formula for the distance between two points.

$r = D = \sqrt{(0 - 0)^{2} + (10 - 0)^{2}} = 10$

$x^{2} + y^{2} = 10^{2}$

$x^{2} + y^{2} = 100$

3 0

3 years ago

Find the area of a circle

PtichkaEL [24]

Answer:

28.26 square feet

Step-by-step explanation:

Area of a circle is: $A=\pi r^2$

'r' is the radius.

We are given the diameter of 6ft. Since the diameter is twice the radius, the radius is 3 ft.

6/2 = 3

Using 3.14 for pi:

$A=3.14*3^2\\\rightarrow 3^2=9\\A=3.14*9\\\boxed{A=28.26}$

The area of the circle should be 28.26 square feet.

7 0

3 years ago

Read 2 more answers

Please Complete the page.

Alexxandr [17]

7. -8/3
8. 4/35
9. -21/50
10. 35/64
11.-25/54

6 0

3 years ago

Which method is best to use to solve the equation 4x2−29=0?(1 point)

makkiz [27]

Answer:

i think factoring

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What are the solutions for x when y is equal to 0 in the following quadratic

Scrat [10]

Answer: Option C

Step-by-step explanation:

Given the quadratic equation $y = x^2 - 13x$ , substitute $y=0$ :

$0 = x^2 - 13x$

In this case, to find the solutions of the given quadratic equation, you must factor out the variable "x". Then:

$0=x(x-13)$

Therefore, you get that the solutions of this equation are the following:

$x=0\\\\\\x-13=0\\x=13$

Then, the answer is:

$x = 0\ or\ x = 13$

This matches with the option C.

5 0

3 years ago