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Art [367]
3 years ago
10

Hello im bored need friends whats 5+5 JK

Mathematics
2 answers:
alex41 [277]3 years ago
6 0

Answer:

Ngl I bored too

jeka943 years ago
3 0

Answer:

Here.........lol

10

I knew you were kidding.....

Follow me

:D

You might be interested in
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
What is a relative frequency?
SVETLANKA909090 [29]

Answer:

"A relative frequency distribution is a table that shows the relative frequency for all categories as shown below. Notice that the sum of the relative frequencies is always equal to 1. The percentage of a category is found by multiplying the relative frequency of that category by 100."

Credits To: statistics-made-easy.com › what-is-relative-frequency

4 0
3 years ago
IL COSL al we creeree viall
kakasveta [241]

Answer:

<em>In the next year, Anthony worked 2,084 hours</em>

Step-by-step explanation:

Anthony worked 1,697 hours in 2010.

We also know Anthony worked 22.8% more hours than in 2010.

The problem requires to calculate how much did Anthony work in the next year.

It can be calculated as follows:

Take 22.8% of 1,697:

22.8 * 1,697 / 100 = 386.916\approx 387\ hours

Now calculate by adding it to the original number of hours:

1,697 + 387 = 2,084 hours

In the next year, Anthony worked 2,084 hours

8 0
3 years ago
Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,
alekssr [168]
Hey there :)

- tan²x + sec²x = 1    or    1 + tan²x = sec²x

sin²x + cos²x = 1 
Divide the whole by cos²x

\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}

\frac{sinx}{cosx} = tanx so \frac{sin^2x}{cos^2x} = tan^2x
and
\frac{1}{cosx} = secx so \frac{1}{cos^2x} = sec^2x

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0
3 years ago
Does any body know math
olga nikolaevna [1]

Answer:

yes I do

Step-by-step explanation:

can you help me with my question In the extended simile of the underlined passage from Paragraph 15 of "A Wagner Matinee," the narrator makes an observation about the soul that aring rokol been A. it is like a strange moss on a dusty shelf that, with excruciating suffering, can wither and die y for I the be B though after excruciating suffering it may seem to wither, the soul never dies, C. excruciating, interminable suffering that goes on for half a century can kill the soul.

4 0
3 years ago
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