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marusya05 [52]
3 years ago
9

The surface area of a cube is 96 square inches. What is the length of one of the sides of the cube?

Mathematics
2 answers:
nadezda [96]3 years ago
5 0

Answer:

4in

Step-by-step explanation:

I had the same problem but revirsed

suter [353]3 years ago
4 0

Answer:

4 in.

Step-by-step explanation:

The surface area of a cube is the area of one of the faces times 6 for each face.

96/6=16

16 is the area of one face of the cube.

The side of the face is the square root of the area of the face.

√16=4

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The endpoints of a diameter of a circle are A(2,1) and B(5,5). Find the area of the circle in terms of pi.
Tcecarenko [31]

Answer:

The area of the circle is A=6.25\pi\ units^{2}

Step-by-step explanation:

step 1

Find the diameter of circle

we know that

The diameter of the circle is equal to the distance AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

AB=\sqrt{(5-1)^{2}+(5-2)^{2}}

AB=\sqrt{(4)^{2}+(3)^{2}}

AB=\sqrt{25}

AB=5\ units

therefore

the diameter of the circle is

D=5\ units  

step 2

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

r=5/2=2.5\ units  ----> the radius is half the diameter

substitute

A=\pi (2.5)^{2}

A=6.25\pi\ units^{2}

4 0
3 years ago
I need help with both of these problems
GREYUIT [131]
The first question is D because if the
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8 0
4 years ago
If 20 pounds of beans sold for $1.20, what was the price per pound of beans?
zaharov [31]

Answer:

0.06 Cent

Step-by-step explanation:

Per Pound= Every one

so 1.20 divided by 20

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So the price per pound of beans is 0.06 Cent

7 0
3 years ago
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EleoNora [17]

Answer:

x is any integer except for -1

Step-by-step explanation:

If you substitute -1 for x, the denominator value would be 0, or undefined.

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exis [7]

Answer:

12.5%

Step-by-step explanation:

[First Value – Second Value] ÷ [(First Value + Second Value) ÷ 2] × 100

[50 - 30] ÷ [ 50 + 30] ÷ 2 × 100

20 ÷ 80 ÷ 2 × 100

0.25 ÷ 2 × 100

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8 0
3 years ago
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