You can do a quick division to figure this out:
2 L / (0.21 L/day) = 9.5 days
F(-4)= -3(-4)^2 + 5(-4)=-68
Option C is correct.
Hope it is useful!!
Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So






Rounding up
We need a sample size of 564.
So my take on this
15 + 3 -2(2 - 1)
15 + 3 -2(1)
15 +3 -2
18 - 2 = 16