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yawa3891 [41]
3 years ago
10

Which of the following scatterplots would have a trend line with a positive slope?

Mathematics
2 answers:
labwork [276]3 years ago
8 0

Answer:a

Step-by-step explanation:

ollegr [7]3 years ago
8 0

Answer:

The answer is A

Step-by-step explanation:

Edge 2021

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I need help its hard plz I'm trying to do a test and I need help plz I will give u 5 stars and a heart plz I have asked 6 times
notka56 [123]

Answer:

-6.8 becauseyou would divide -34 by 5.

4 0
3 years ago
Read 2 more answers
Juan has 2 liters of juice he drinks 0.21 each day for how many days will the juice last
inna [77]
You can do a quick division to figure this out:

2 L / (0.21 L/day) = 9.5 days
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3 years ago
What is the value of the dependent variable if the value of the independent variable is -4?
umka2103 [35]
F(-4)= -3(-4)^2 + 5(-4)=-68
Option C is correct.
Hope it is useful!!
5 0
3 years ago
Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c
nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = \frac{81}{130} = 0.6231

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when M = 0.04

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.6231*0.3769}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.6231*0.3769}

\sqrt{n} = \frac{1.96\sqrt{0.6231*0.3769}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.6231*0.3769}}{0.04})^{2}

n = 563.8

Rounding up

We need a sample size of 564.

4 0
3 years ago
Please Simplify the expression 15 + 3 - 2(2 - 1) Thanks in advance!
liberstina [14]
So my take on this
15 + 3 -2(2 - 1)
15 + 3 -2(1)
15 +3 -2
18 - 2 = 16
8 0
3 years ago
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