Sqr root 8+3 Sqr root 2+ Sqr root 32 simplest form

Mathematics

1 answer:

Kisachek [45]3 years ago

6 0

Answer:

<u> $9\sqrt{2}$ </u>

Step-by-step explanation:

The given question is :

$\sqrt{8} +3\sqrt{2} +\sqrt{32}$

8 = 4 * 2

32 = 16 * 2

$\sqrt{8} =\sqrt{4*2} = 2\sqrt{2} \\\sqrt{32} =\sqrt{16*2} =4\sqrt{2}$

∴ $\sqrt{8} +3\sqrt{2} +\sqrt{32}$

= $2\sqrt{2} +3\sqrt{2} +4\sqrt{2}$

= $9\sqrt{2}$

You might be interested in

This rational expression is nonequivalent. 5x / 25x^4 ; x^3 / 5x^15<br> True or false?????

FromTheMoon [43]

It is nonequivalent. Figure it out this way. Think about what number has to be multiplied by both the numerator and the denominator of $\frac{5x}{25x^4}$ to get to $\frac{x^3}{5x^15}$ . It has to be the samee number for the one expression to be equivalent to the other. To get from 5x to x^3, we have to multiply by 1/5x^2. When we do that we get x^3. Good. Now we have to multiply the denominator by the same thing, 1/5x^2. $25x^4(\frac{1}{5}x^2)=5x^6$ . As you can see, they are not equivalent.