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Sholpan [36]
3 years ago
10

Will mark brainliest if you have the full practice answers!!!

Mathematics
1 answer:
dybincka [34]3 years ago
8 0

Answer:

1. D (x-5)^2-(y-2/2)^2=1

2. A

3. C No. The car travels counterclockwise in a circle at the origin with radius 2.

Step-by-step explanation:

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The lengths (in miles) of two highways after t years of construction can be modeled by 20t + 150 and 15t+ 200. What is the diffe
Mashutka [201]

Step-by-step explanation:

13.5 is the difference of the length of the roads

3 0
2 years ago
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
Please help me out on this one
vivado [14]

it is definitely the answer B

8 0
3 years ago
Which answers the graph ?
s344n2d4d5 [400]
y+2\leq-\dfrac{2}{3}+4\ \ \ |-2\\\\y\leq-\dfrac{2}{3}x+2

Answer: B. Graph B

4 0
3 years ago
Describe another method to compare cost
scZoUnD [109]
3:1 because your comparing the 3 to the 1
You can get one bunny for every three dogs.
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