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andrey2020 [161]
3 years ago
6

8x+4= I just need the answer

Mathematics
2 answers:
Zigmanuir [339]3 years ago
5 0

this equation is unanswerable, there is no way to find x.

Step-by-step explanation:

faltersainse [42]3 years ago
5 0
You can’t solve this, nothing would make sense
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The number of parking tickets issued in a certain city on
Katyanochek1 [597]
I am going to say it is probably ....B....
8 0
4 years ago
Solve for x:<br> (x - 1)(3x + 1) = 0
sleet_krkn [62]

Answer:

x=1 and x=-1/3

Step-by-step explanation:

By the zero product property, we have two separate equations, x-1=0 and 3x+1=0

x-1=0

x=1

3x+1=0

3x=-1

x=-1/3

So x=1 and x=-1/3

Hope this helped!

6 0
3 years ago
Please help!!!!!
fgiga [73]

Answer:

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3 years ago
Four red, 8 blue, and 5 green balls are randomly arranged in a line. (a) What is the probability that the first 5 balls are blue
Over [174]

Answer:

it may be 3

Step-by-step explanation:

it may be bcz am not much good but still just trying

3 0
2 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
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