All categories

2 years ago

Surface area of 9cm, 10cm, and 15cm

Mathematics

1 answer:

AVprozaik [17]2 years ago

8 0

Answer: The answer is 750 cm

You might be interested in

Find the area of a triangle help

erastova [34]

Hi there!

• Base, b = 8 units
• Altitude, a = 10 units

Area of Triangle = $\dfrac{1}{2}$ × b × a = $\dfrac{1}{2}$ × 8 × 10 = 40 units.

Hence,
Th' required area of triangle is 40 units

~ Hope it helps!

5 0

2 years ago

Read 2 more answers

Nicolas says that (2^6)(2^6) equals 2^12 and also equals 4^6 . Do you agree?

alex41 [277]

Answer:

Nicolas is correct.

4^6 =4096

2^12 = 4096

4 0

2 years ago

Please someone help me. Im giving brainliest !!!!

prohojiy [21]

Answer:

Each room can hold 30.

Step-by-step explanation:

90/3=30.

8 0

2 years ago

Read 2 more answers

Why does it pi appear in measurement formulas involving circles?

diamong [38]

Answer:

because it is the ratio or the quotient of the circumference

Step-by-step explanation:

C (the distance around a circle) to the diameter d (the distance across a circle through the center of the circle)

8 0

2 years ago

Please prove the following identity

Sedaia [141]

Let's remember the factorizations

$a^3 + b^3 = (a+b)(a^2-ab+b^2)$

$a^3- b^3=(a-b)(a^2+ab+b^2)$

Now

$\dfrac{\sin ^3 \theta + \cos^3 \theta}{\sin \theta + \cos \theta} + \dfrac{\sin^3 \theta - \cos^3 \theta}{\sin \theta - \cos \theta}$

$=\dfrac{(\sin \theta + \cos \theta)(\sin ^2 \theta - \sin \theta\cos \theta + \cos^2 \theta)}{\sin \theta + \cos \theta} + \dfrac{(\sin \theta - \cos \theta)(\sin^2 \theta + \sin \theta \cos \theta + \cos^2 \theta)}{\sin \theta - \cos \theta}$

$=\sin ^2 \theta - \sin \theta\cos \theta + \cos^2 \theta + \sin^2 \theta + \sin \theta \cos \theta + \cos^2 \theta$

$=\sin ^2 \theta + \cos^2 \theta + \sin^2 \theta+ \cos^2 \theta$

$=2 \quad\checkmark$

4 0

3 years ago