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2 years ago

Just need a little help thanks

Mathematics

1 answer:

Naya [18.7K]2 years ago

3 0

Answer:

D similar by AA

Step-by-step explanation:

L B = L D ( right angle)

L BCA = L DCE (push back angle)

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Geometry question please help

Licemer1 [7]

Answer:

BE=AD

Step-by-step explanation:

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3 years ago

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Helpppppppp Will give brainly

babunello [35]

Answer:

20.5 is the answer!! all you have to do is add em.

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2 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

We can conclude that the change to the face 3 affects the value of P(Odd Number)

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2 years ago

Which data collections show bias? Check all that apply.

V125BC [204]

Answer:

An insurance company polls drivers of sports cars to find their average number of tickets.

Step-by-step explanation:

It’s bias because they’re only polling people with sports cars

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2 years ago

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HELP ME ASAP

MArishka [77]

1)

a.
60 ounces = 3 pounds

So no, you don’t have as much fruit as you need.

b.
60 ounces —> 3 pounds
X ounces —> 4 pounds

Cross product :

(60 x 4) / 3 —> 240/3 = 80

So in order to have 4 pounds of fruits, you need 80 ounces of fruits.

You already have 60 ounces of fruits.

X + 60 = 80

80 - 60 = X

20 = X

You need 20 more ounces to have 4 pounds of fruits.

:)

5 0

3 years ago