Given:
Number of trips = 7
Distance from the school to the museum = 36 miles.
To find:
Write and solve equations to find how many miles the bus driver drove for the 7 trips.
Solution:
Let x be the number of trips and y be the total number of miles the bus driver drove.
Distance from the school to the museum = 36 miles.
1 trip means from the school to the museum and then from the museum to the school.
Distance covered in 1 trip = 2×36 = 72 miles.
Distance covered in x trips = 72x miles.

Substitute x=7 in the above equation to find the total distance the bus driver drove for the 7 trips.


Therefore, the bus driver drove 504 miles for the 7 trips.
Answer:
7/9, -0.3, 11/2
Step-by-step explanation:
Step-by-step explanation:
y=k/x
y=20, x=2
Substitute this first to get "k"
20=k/2
k=40
Value of y when x=10... is now
y= 40/10
y=4.
Answer:

Step-by-step explanation:
![\displaystyle a^2 + 2a\sqrt{\frac{a^2}{4} + h^2} = S.A. \\ \\ 14^2 + 2[14]\sqrt{\frac{14^2}{4} + 19^2} = S.A. \\ \\ 196 + 28\sqrt{\frac{196}{4} + 361} ≈ 762,9567885 ≈ 762,96](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%5E2%20%2B%202a%5Csqrt%7B%5Cfrac%7Ba%5E2%7D%7B4%7D%20%2B%20h%5E2%7D%20%3D%20S.A.%20%5C%5C%20%5C%5C%20%2014%5E2%20%2B%202%5B14%5D%5Csqrt%7B%5Cfrac%7B14%5E2%7D%7B4%7D%20%2B%2019%5E2%7D%20%3D%20S.A.%20%5C%5C%20%5C%5C%20196%20%2B%2028%5Csqrt%7B%5Cfrac%7B196%7D%7B4%7D%20%2B%20361%7D%20%E2%89%88%20762%2C9567885%20%E2%89%88%20762%2C96)
I am joyous to assist you anytime.
As the GCF is 3x let us write a polynomial and then multiply it by 3x.
Here is a polynomial:

If we multiply it by 3x we get

. Since we have a product (two expressions being multiplied together) this is factored. So this is the factored form of the polynomial we created with GCF of 3x.
Let’s multiply the terms in the parenthesis by 3x to get the same polynomial but written a different way:

. This is the factorable polynomial and the one we had before is the factored polynomial (also an equivalent form)
To get another equivalent form I could multiply out only the first term. This gives us

another equivalent form.