Answer:
The missing figure is attached down
The length of BE is 27 units ⇒ 3rd answer
Step-by-step explanation:
In circle A:
- ∠BAE ≅ ∠DAE
- Line segments A B, A E, and A D are radii
- Lines are drawn from point B to point E and from point E to point D to form secants B E and E D
- The length of B E is 3 x minus 24 and the length of E D is x + 10
We need to find the length of BE
∵ AB and AD are radii in circle A
∴ AB ≅ AD
In Δs EAB and EAD
∵ ∠BAE ≅ ∠DAE ⇒ given
∵ AB = AD ⇒ proved
∵ EA = EA ⇒ common side in the two triangles
- Two triangles have two corresponding sides equal and the
including angles between them are equal, then the two
triangles are congruent by SAS postulate of congruence
∴ Δ EAB ≅ Δ EAD ⇒ SAS postulate of congruence
By using the result of congruence
∴ EB ≅ ED
∵ EB = 3 x - 24
∵ ED = x + 10
- Equate the two expressions to find x
∴ 3 x - 24 = x + 10
- Add 24 to both sides
∴ 3 x = x + 34
- Subtract x from both sides
∴ 2 x = 34
- Divide both sides by 2
∴ x = 17
Substitute the value of x in the expression of the length of BE to find its length
∵ BE = 3 x - 24
∵ x = 17
∴ BE = 3(17) - 24
∴ BE = 51 - 24
∴ BE = 27
The length of BE is 27 units
Answer:
x = 63
Step-by-step explanation:
Using proportion to solve for x
=
( cross- multiply )
2x = 126 ( divide both sides by 2 )
x = 63
Step-by-step explanation:
do you mean 6.70 because if you do I think it is 7 but I am not sure
I don't like dividing polynomials so I'm going to set x=1 and try them out.
(1-2-14+3)/4 = -3
Of the choices, only D gives -3 when x=1
~~~~~~~~~~~~~~~~~~~~~~
That's as much test-taking as math. If we were to divide
x^2 - 5x + 1
-------------------------------
x + 3 | x^3 - 2x^2 - 14x + 3
x^3 + 3x^2
-5x^2 - 14x
5x^2 + 15x
x + 3
x + 3
More work, still choice D

You can find the oblique asymptote by dividing the polynomial in the numerator by the polynomial in the denominator. The asymptote is the result of the division, without the remainder.
Look at the picture.
The oblique asymptote is

.