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alexgriva [62]
3 years ago
8

Find the set of values of x for which y is zero inthe equation y=(x + 2) (2x-2)​

Mathematics
1 answer:
Alex777 [14]3 years ago
8 0

Answer:

{ - 2, 1 }

Step-by-step explanation:

To determine the values let y = 0, that is

(x + 2)(2x - 2) = 0 ← in standard form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

2x - 2 = 0 ⇒ 2x = 2 ⇒ x = 1

The set of values are { - 2, 1 }

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andrew11 [14]
Ok? Is there like an equation or something that I can see so then I can help you?
4 0
3 years ago
Two trucks are traveling in the same direction, one going twice as fast as the other. At the end of 6 hours they are 204 miles a
TEA [102]

Answer:

34 mph and 68 mph respectively

Step-by-step explanation:

Step one:

given data

let the speed of the first truck be x mph

and the speed of the second truck be 2x mph

time taken = 6 hours

total distance = 204 miles

Step two:

from speed = distance/time

distance= speed*time

hence

2x*6-6x= 204

12x+6x= 204

6x= 204

divide both side by 6

x= 204/6

x=34 mph

The second truck was moving at

=2x

=2*34

=68 mph

7 0
3 years ago
Question 1 help pls ​
Evgesh-ka [11]

Answer:

y = - \frac{1}{2} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = \frac{0-2}{4-0} = \frac{-2}{4} = - \frac{1}{2}

note the line crosses the y- axis at (0, 2) ⇒ c = 2

y = - \frac{1}{2} x + 2 ← equation of line

4 0
3 years ago
Round each number to the nearest 10 and 100<br><br> 998<br> 274<br> 533
Pepsi [2]

Hello!

998 rounded to the nearest 10 is 1000. It is also 1000 when rounded to the nearest 100.

274 rounded to the nearest 10 is 270. 274 rounded to the nearest 100 turns it into 300.

533 to the nearest 10 is 530. It is 500 when rounded to the nearest 100.

I hope this helps you!

- Mal

6 0
4 years ago
HELP PLSSS PLS DONT GET IT WRONG!!
podryga [215]

\frac{2(a^{2})^3 }{-10a^{-8} } =\frac{2a^6}{-10a^{-8} } = \frac{-1}{5} a^{6--8} =\frac{-1}{5} a^{14}

Hope that helps!

4 0
3 years ago
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