So it's best in this case to separate both shapes so you have a rectangle and a triangle so to solve the area of a rectangle you do
The following ( picture )
So I hope this helps
Answer:
f(x) = 4x^2 + 2x - 4.
Step-by-step explanation:
Let the quadratic function be y = f(x) = ax^2 + bx + c.
For the point (-2, 8) ( x = -2 when y = 8) we have:
a(-2)^2 + (-2)b + c = 8
4a - 2b + c = 8 For (0, -4) we have:
0 + 0 + c = -4 so c = -4. For (4, 68) we have:
16a + 4b + c = 68
So we have 2 systems of equations in a and b ( plugging in c = -4):
4a - 2b - 4 = 8
16a + 4b - 4 = 68
4a - 2b = 12
16a + 4b = 72 Multiplying 4a - 2b = 12 by 2 we get:
8a - 4b = 24
Adding the last 2 equations:
24a = 96
a = 4
Now plugging a = 4 and c = -4 in the first equation:
4(4) - 2b - 4 = 8
-2b = 8 - 16 + 4 = -4
b = 2.
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I did it on my calculater and the answer came as 13
hope that helps :)
Answer:
(3y - 2)(2y - 7)
Step-by-step explanation:
To factorise the quadratic
Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term
Product = 6 × 14 = 84 and sum = - 25
The required factors are - 4 and - 21
Use these factors to split the y- term
6y² - 4y - 21y + 14 ( factor the first/second and third/fourth terms )
2y(3y - 2) - 7(3y - 2) ← factor out (3y - 2) from each term
= (3y - 2)(2y - 7) ← in factored form
Answer:
Step-by-step explanation:
x + 13 + 4x + 2 = 180
Add the like terms,
5x + 15 = 180
Subtract 15 form both sides
5x + 15 - 15 = 180 -15
5x = 165
Divide both sides by 5
5x/5 = 16/5
x = 33
