You can't really make it easier to add, but since the (8+25) is in parentheses you should add that first
52 + 33
Then add straight away
52 + (8+25) = 85
Your first point would be on (0, 2), the vertex. Then, put a point on (-2, 22). Hope that helps!
Answer:
ABCD is not a parallelogram
Step-by-step explanation:
Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)
We have to find the length of the sides of the parallelogram using the formula below
= √(x2 - x1)² + (y2 - y1)² when given vertices (x1, y1) and (x2, y2)
For side AB
A(-3,2) B(-3,3)
= √(-3 -(-3))² + (3 -2)²
= √0² + 1²
= √1
= 1 unit
For side BC
B(-3,3) C (5,-3)
= √(5 -(-3))² + (-3 -3)²
= √8² + -6²
= √64 + 36
= √100
= 10 units
For side CD
C (5,-3) D (-1.-5)
= √(-1 - 5)² + (-5 - (-3))²
= √-6² + -2²
= √36 + 4
= √40 units
For sides AD
A(-3,2) D (-1.-5)
= √(-1 - (-3))² + (-5 -2)²
= √(2² + -7²)
= √(4 + 49)
= √53 units
A parallelogram is a quadrilateral with it's opposite sides equal
From the above calculation
Side AB ≠ CD
BC ≠ AD
Therefore, ABCD is not a parallelogram
Start by writing the system down, I will use 
to represent 
Substitute the fact that 
into the first equation to get,
Simplify into a quadratic form (
),
Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,
which then must factor into
And the solutions will be 
.
Clearly for small coefficients like ours 
, this is very easy to figure out. To get 5 and 6 we simply say that 
.
This fits the definition as 
and 
.
So as mentioned, solutions will equal to but these are just x-values in the solution pairs of a form 
.
To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.
So the solution pairs are 
and 
.
Hope this helps :)
Answer:
y = -5/2x - 13
Step-by-step explanation:
First, we have to find the slope of the original equation
Subtract 5x from both sides
5x + 2y = 1
- 5x - 5x
2y = -5x + 1
Divide both sides by 2
2y/2 = (-5x + 1)/2
y = -5/2x + 1/2
The slope of this equation is -5/2, so -5/2 has to be in our new parallel equation
y = -5/2x + b
Plug in the given x and y
-3 = -5/2(-2) + b
-3 = 10 + b
Subtract 10 from both sides
-3 = 10 + b
- 10 - 10
b = -13
This makes our equation: y = -5/2x - 13
