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3 years ago

"Find the coefficient of determination given that the correlation coefficient = -.39"

Mathematics

1 answer:

nika2105 [10]3 years ago

4 0

Answer:

$r = -0.39$

And the determination coeffcient is just the correlation coeffcient square and we got:

$R = r^2 = (-0.39)^2 =0.1521$

And rounded to the nearest tenth thousand would be 0.1521

Step-by-step explanation:

The correlation coefficient is a measure of variability and is given by this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For this case we have

$r = -0.39$

And the determination coeffcient is just the correlation coeffcient square and we got:

$R = r^2 = (-0.39)^2 =0.1521$

And rounded to the nearest tenth thousand would be 0.1521

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Answer:

See below.

Step-by-step explanation:

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Use the cofunction identities. The cofunction identities are:

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To convert this, factor out a negative one from the cosine and sine.

$\frac{\cos(-(\frac{\pi}{2}-x ))}{\sin(-(\frac{\pi}{2}-x))} =-\tan(x)$

Recall that since cosine is an even function, we can remove the negative. Since sine is an odd function, we can move the negative outside:

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Answer:

Step-by-step explanation:

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