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STALIN [3.7K]
1 year ago
11

] Complete the explanation of how you know whether the triangles are similar. If possible, find the Indicated length. A P 2.0 1.

7 B B Q 1.2 C С R Because two pairs of angles are congruent, the triangles are similar by the SSS Triangle Similarity Theorem QR =

Mathematics
1 answer:
disa [49]1 year ago
5 0

1. The two triangles are similar because the two pairs of angles are equal, therefore the third angles of both triangles must also be equal.

We can call this the AAA similarity criterion

2. To find QR, we must use ratios between 2 known similar sides of both triangles,

\frac{2.0}{1.7}=\frac{1.2}{QR}\text{  , QR=}\frac{1.2\times1.7}{2.0}=\text{ 1.02}

So, QR =1.02

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Please help I will mark brainliest
den301095 [7]

Answer:

Choice 1) no

Choice 2) yes

Choice 3) yes

Choice 4) no

Choice 5) yes

Choice 6) no

6 0
2 years ago
Read 2 more answers
A regulation basketball has a diameter of about 9 in. What is the best approximation for the volume of this ball? 3050 in³ 382 i
Mandarinka [93]

The best apporximation for the volume of this ball is 382 cubic inches.

<h3>What is the volume of the ball?</h3>

The volume of the ball is calculated by the formula V = 4 / 3πr³. This formula is the same in the whole world.

Given

A regulation basketball has a diameter of about 9 in.

The radius of the ball is;

\rm Radius = \dfrac{Diameter}{2}\\\\Radius=\dfrac{9}{2}\\\\Radius=4.5\ inches

The volume of the ball is;

\rm Volume =\dfrac{4}{3}\pi r^3\\\\Volume=\dfrac{4}{3} \times 3.14 \times 4.5^3\\\\Volume =\dfrac{144.53}{3}\\\\Volume = 381.51\\\\Volume = 382 \ In^3 \ apporx

Hence, the best apporximation for the volume of this ball is 382 cubic inches.

To know more about volume click the link given below.

brainly.com/question/10647788

4 0
2 years ago
Can u please help me
EleoNora [17]
You will have to divide 140 by 8 and it will give u P you already know R equals 8
5 0
3 years ago
A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

  • z = 0.52,
  • x =5, and
  • \sigma = 2,

Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

3 0
3 years ago
A student solved the following problem and made an error:
liubo4ka [24]

All the steps were correct except the final statement. The mistake was in Line 6.

Line 6 triangle ABC is congruent to triangle EFD by SAS.

<span>This does not follow. The SAS postulate states that if two sides and the included angle of one triangle is congruent to two sides and the included angle of another triangle. The student only proved that one side of the triangle (AC) is congruent to the side of another triangle (EF) .</span>

8 0
3 years ago
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