How high must a sack of sugar weighing 10 kg be lifted to have 58 J of potential energy? (Hint: Derive the formula of PE-mgh to get the formula for height. Divide both sides by the variable/s adjacent to height (h) to get h=PE/mg)

G : 58J (PE) and 10 kg (mass)

E : h = PE/mg

S : 58J/(10kg)(9.8/2)

A : 58/59 = [ 0.59 m ]

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If a bicycle with a velocity of 17.89 has kinetic energy of 5000 J. What is the mass of the bicycie? (Hint: Derive the formula of KE my to get the formula for mass. Divide both sides by the variable/s adjacent to the mass (h) to get m=KEEP/(0.5)(v²)

G : v = 17.89 m/s

KE = 5000J

E : m = KE/0.5v²

S : m = KE/0.5v²

= 5000J/(0.5)(17.89 m/s²)

= 5000J/160.02605 m²/s²

= 31.2449 kg

A : m = [ 31 kg ]

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2 years ago

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Hi I'm new please cooperate me I'm from India... please follow me