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seropon [69]
3 years ago
7

The total of fifteen and a number p

Mathematics
1 answer:
JulsSmile [24]3 years ago
7 0
15 + p = ? 
I hope this helps :)
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Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
A line passes through the point (-3,-3) and had a slope of 1/2, what equation is the line?
azamat

Answer:

y + 3 = 1/2(x + 3)

Step-by-step explanation:

Point Slope Form: y - y1(y coordinate) = m(slope)(x - x1(x coordinate))

4 0
2 years ago
Calculate the product: 4/5 x 55
Mars2501 [29]
4/5 x55
=4/5*55/1
=(4*55)/(5*1)
=220/5
=44/1
=44
5 0
3 years ago
What's is 1 + 1 please help idk this
alexandr402 [8]

Answer:

One plus one is two.

Step-by-step explanation:

3 0
3 years ago
Solve<br>2x + 5x - 11 = -46​
irga5000 [103]

Answer:

Step-by-step explanation:

7x-11=-46

(7x-11)+11=-46+11

X = -5

5 0
3 years ago
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