Rewrite the polynomial in the form ax^2 + bx + C and then identify the values of a, b, and c.

Mathematics

1 answer:

sergejj [24]3 years ago

8 0

Answer:

$a = 5\\\\b = -1\\\\c=1$

Step-by-step explanation:

Given

$-x+5x^2+1$

Required

Rewrite and identify a, b and c

The required form is:

$ax^2 + bx + c$

Equate both expressions

$ax^2 + bx + c = -x+5x^2+1$

Rewrite as:

$ax^2 + bx + c = 5x^2-x+1$

Compare the expressions on either sides

$a = 5\\\\b = -1\\\\c=1$

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Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

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