Answer:
Step-by-step explanation:
The diagram shows lines passing through the points of two equations.
We will determine the points through which the lines pass through on the graphs.
Looking at the line on the right hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 4
x2 = 3, x1=0
Slope, m = (0-4)/3-0
Slope = -4/3
Recall the equation of a straight line is y = mx + c
Where c is the intercept.
So the equation is y
y = -4x/3 + 4
Looking at the line on the left hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 2
x2 = -1, x1 =0
Slope, m = (0-2)/-1-0
Slope = -2/-1 = 2
Applying equation of a straight line is y = mx + c
The equation
y = 2x + 2
So the equations are
-4x/3 + 4. If x lesser than or equal 0
2x + 2. If x greater than 0
First, lets transform the given vector into an unit vector (dividing by its module)
UnitVec = 4/5 i + 3/5 j
Then lets change this vector into a polar form
UnitVec = 1. with angle of 36.869 degrees taking as a reference the i vector
Then, the probem tells us that the vectors u and v make an angle of 45 degrees with UnitVec, so lets add+-45 to the vector in polar form
U = 1*[cos(36.869 +45)i + sin(36.869 +45)j] = 0.1414 i + 0.9899 j
V = 1*[cos(36.869 -45)i + sin(36.869 -45)j] = 0.9899 i - 0.1414 j
Answer:
Step-by-step explanation:
Let 
represent the number of hours Gary must work per week.
The contract states that Garry must work more than 20 hours.
This can be represented algebraically by the inequality;
We know, Volume of a Cube = Edge³
so, it would be: f(v) = a³
Hope this helps!
