well, the assumption is that is a rectangle, namely it has two equal pairs, so we can just find the length of one of the pairs to get the dimensions.
hmmmm let's say let's get the length of the segment at (-1,-3), (1,3) for its length
and
the length of the segment at (-1, -3), (-4, -2) for its width
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{length}{L}=\sqrt{[1-(-1)]^2+[3-(-3)]^2}\implies L=\sqrt{(1+1)^2+(3+3)^2} \\\\\\ L=\sqrt{4+36}\implies L=\sqrt{40} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B-3%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B1%7D~%2C~%5Cstackrel%7By_2%7D%7B3%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Blength%7D%7BL%7D%3D%5Csqrt%7B%5B1-%28-1%29%5D%5E2%2B%5B3-%28-3%29%5D%5E2%7D%5Cimplies%20L%3D%5Csqrt%7B%281%2B1%29%5E2%2B%283%2B3%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20L%3D%5Csqrt%7B4%2B36%7D%5Cimplies%20L%3D%5Csqrt%7B40%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{width}{w}=\sqrt{[-4-(-1)]^2+[-2-(-3)]^2}\implies w=\sqrt{(-4+1)^2+(-2+3)^2} \\\\\\ w=\sqrt{9+1}\implies w=\sqrt{10} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{A=Lw}\implies \sqrt{40}\cdot \sqrt{10}\implies \sqrt{400}\implies \boxed{20}](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B-3%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B-4%7D~%2C~%5Cstackrel%7By_2%7D%7B-2%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Bwidth%7D%7Bw%7D%3D%5Csqrt%7B%5B-4-%28-1%29%5D%5E2%2B%5B-2-%28-3%29%5D%5E2%7D%5Cimplies%20w%3D%5Csqrt%7B%28-4%2B1%29%5E2%2B%28-2%2B3%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20w%3D%5Csqrt%7B9%2B1%7D%5Cimplies%20w%3D%5Csqrt%7B10%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20rectangle%7D%7D%7BA%3DLw%7D%5Cimplies%20%5Csqrt%7B40%7D%5Ccdot%20%5Csqrt%7B10%7D%5Cimplies%20%5Csqrt%7B400%7D%5Cimplies%20%5Cboxed%7B20%7D)
Answer:
Step-by-step explanation:
We can get this done by using the code
def digits(n):
count = 0
if n == 0:
return 1
while (n > 0):
count += 1
n= n//10
return count
Also, another way of putting it is by saying
def digits(n):
return len(str(n))
------------------------------------------
print(digits(25)) # Should print 2
print(digits(144)) # Should print 3
print(digits(1000)) # Should print 4
print(digits(0)) # Should print 1
Doing this way, we've told the system to count the number of figures that exist in the number. If it's 1000 to 9999, then it records it as 4 digits. If it's 100 - 999, then it records it as 3 digits. If it's 10 - 99, it records as 2 digits. If it's 0 - 9, then it has to record it as a single digit.
Thanks
Answer: O AAS Congruence Theorem is your answer
Step-by-step explanation: plz give brainliest
Answer:
D. (6,3)
Step-by-step explanation:
To the find which point can be located on the line you will have to find the point-slope form
The formula for point-slope form is y=mx+b
m is slope
b is y-intercept
Since we already know the slope we can just replace it:
y=1/2x+b
Now we need to find the y-intercept
We can do this by distributing them with (4,2)
As you remember in point the digits are in x and y
(x,y) so we can tell that 4 is x and 2 is y
Now we can substitute x with 4 and y with 2
2=1/2(4)+b
Multiply 1/2 and 4
which is 2
2=2+b
Thus b=0
So the slope intercept form is y=1/2x
Now we can substitute the other points:
For (5,2):
2=5/2
Which is incorrect since 2 does not equal 5/2
For (2,3):
3=1/2(2)
Which is
3=1
Which is incorrect since 3 does not equal 1
For (3,4)
4=1/2(3)
Which is
4=3/2
Which is incorrect since 4 does not equal 3/2
For (6,3)
3=1/2(6)
Which is
3=3
Which is correct since 3 does equal to 3
Hope this helps!
Answer:
The correct answer is B- 21b+7bc
Step-by-step explanation:
7b(3+c)
(7b)(3+c)
(7b)(3)+(7b)(c)
21b+7bc
