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const2013 [10]
3 years ago
7

Levi invested $5,300 in an account paying an interest rate of 2.4% compounded daily. Assuming no deposits or withdrawals are mad

e, how much money, to the nearest cent, would be in the account after 6 years?
Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer: $6,120.86

Step-by-step explanation:

Formula to calculate the accumulated amount in n years (compounded daily)  is given by :-

A=P(1+\dfrac{r}{365})^{365\times n}

P= Initial amount

r= Rate of interest ( in decimal)

As per given , we ahve

P= $5300

r= 2.4%=0.024

n= 6 years

Put these values in formula , we get

A=5300(1+\dfrac{0.024}{365})^{365\times6}\\\Rightarrow\ A=5300(1.00006575342)^{2190}\\\Rightarrow\ A=6120.85673631\approx6120.86

Hence, there would be $6,120.86 in the account after 6 years.

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A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric f
likoan [24]

Step-by-step explanation:

Let x be the length and y be the width of the rectangular plot.

The plot is bounded on one side by a river and on the other three sides by a single-strand electric fence. It means,

x+2y = 1500

x = 1500 - 2y ....(1)

We know that the area of a rectangular plot is given by :

A = xy ....(2)

Put the value of x from equation (1) in (2)

A=(1500-2y)y\\\\A=1500y-2y^2 .....(3)

For largest area, differentiate above area equation wrt y.

\dfrac{dA}{dy}=\dfrac{d}{dy}(1500y-2y^2)\\\\=1500-4y\\\\\text{Put}\ \dfrac{dA}{dy}=0\\\\1500-4y=0\\\\y=\dfrac{1500}{4}\\\\=375

Put the value of y in equation (1).

x = 1500-2(375)

= 750 m

Put the value of y in equation (3).

A =1500(375)-2(375)^2\\A=281250\ m^2

Hence, the largest area is 281250 m² and its dimensions are 750 m and 375 m.

3 0
3 years ago
Which pair of angles are alternate exterior angles of parallel lines v and w?
vampirchik [111]

Answer:

a and d

Step-by-step explanation:

v and w are parallel lines

R is the transversal

Alternate exterior means on the opposite sides of the transversal and outside of the parallel linea

a and d are alternate exterior angles

8 0
2 years ago
What is the solution for 2x -4= -8
scoray [572]

Answer:

  x = 48

Step-by-step explanation:

  3x +  9 = 153

 

subtract 9 from both sides               -9       -9

 

                                                     3x = 144

 

divide both sides by 3                    3x/3 = 144/3

2x + (x + 9) = 153

 

2(48) + (48 + 9) = 153

 

96 + 57 = 153

 

153 = 153

8 0
3 years ago
Read 2 more answers
H(x=-10x+6 find h(0)
gtnhenbr [62]

Answer:

h(0) = 6

Step-by-step explanation:

Plug x = 0 to find h(0)

h(0) = -10.0 + 6 = 6

3 0
3 years ago
Read 2 more answers
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
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