1 year ago

The function shown crosses the y-axis at.... (Pls help me ill give brainliest)

Mathematics

1 answer:

allsm [11]1 year ago

5 0

Answer:

(0,3)

Step-by-step explanation:

(x,y)

you need to be on the y-axis and to be on that you need to have 0 on the

x-axis which is the first number you see (if you are reading from left to right)

and you need to go up 3 times so you put a 3 on the y axis and boom there you have it

Hope this helps!

You might be interested in

What is 4 yards and 2 feet multiplied by 3

lesantik [10]

Answer:

12 yds and 6 feet, aka 42 feet.

Step-by-step explanation:

You multiply everything by 3. Then you convert yards to feet, then add everything together.

5 0

2 years ago

Help me with this math question please

Maksim231197 [3]

the solution is where the line cross on the y axis, which is on 0

so y = 0

6 0

2 years ago

Can anyone help me with this question

Lina20 [59]

Answer:

$78$

idont know

5 0

1 year ago

Complete the chart to find the mean, varlance, and standard deviation. Remember to use commas and round numbers to the nearest t

aleksley [76]

Answer:

i dont know sorry

Step-by-step explanation:

5 0

1 year ago

Read 2 more answers

A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the

amm1812

Answer:

$s(t)=(ln|7|+ln|2|)\,ft$

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

$a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\$

Integrating both sides w.r.to t

$v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\$

Using initial value

$v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}$

We have to calculate the distance covered in time interval [0,5], so:

$\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft$

3 0

2 years ago