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3 years ago

5

Pls pls helpp I’ll mark u brainliestttt i

1 answer:

ioda3 years ago

7 0

The answer is:

Mean: 44

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Find the MIDPOINT between (-12, – 7)<br> and (-8,-4).

DanielleElmas [232]

so you take the average of the x coordinates and the average of the y coordinates to get the midpoint like this

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3 years ago

This is the question.<br><br><br><br> solve (3.4)x(0.2)

Umnica [9.8K]

Answer:

0.68

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports

iVinArrow [24]

Answer:

He have <u>15</u> action games and <u>24</u> sports games.

Step-by-step explanation:

Given:

Ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports collection.

Now, to find the number of action games and sports games.

Let the sports games be $x.$

As, given his action collection is three more than half his sports collection.

Thus, the action games = $3+\frac{x}{2}$ .

Total number of video games = 39.

So, we set an equation to get the number of action games and sports games:

$x+(3+\frac{x}{2})=39$

$x+3+\frac{x}{2} =39$

<em>Subtracting both sides by 3 we get:</em>

$x+\frac{x}{2} =36$

$\frac{2x+x}{2}=36$

$\frac{3x}{2} =36$

<em>Multiplying both sides by 2 we get:</em>

$3x=72$

<em>Dividing both sides by 3 we get:</em>

$x=24.$

<u>The sports games he have = 24.</u>

Now, to get the action games we substitute the value of $x$ :

$3+\frac{x}{2}$

= $3+\frac{24}{2}$

= $3+12$

= $15.$

<u>The action games he have = 15.</u>

Therefore, he have 15 action games and 24 sports games.

6 0

3 years ago

Which tool is not needed to construct a perpendicular bisector?

Dafna11 [192]

A compass because youre just making two arcs

8 0

3 years ago

Read 2 more answers

A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of <em>X</em> as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago