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tigry1 [53]
3 years ago
10

Solve for X if 2x-5√X -3 = 0​

Mathematics
2 answers:
Gwar [14]3 years ago
8 0

Answer:

Step-by-step explanation:

2x^2+10x+47 = 0

Simplifying

2x2 + 10x + 47 = 0

Reorder the terms:

47 + 10x + 2x2 = 0

Solving

47 + 10x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by

2 the coefficient of the squared term:  

Divide each side by '2'.

23.5 + 5x + x2 = 0

Move the constant term to the right:

Add '-23.5' to each side of the equation.

23.5 + 5x + -23.5 + x2 = 0 + -23.5

Reorder the terms:

23.5 + -23.5 + 5x + x2 = 0 + -23.5

Combine like terms: 23.5 + -23.5 = 0

0 + 5x + x2 = 0 + -23.5

5x + x2 = 0 + -23.5

Combine like terms: 0 + -23.5 = -23.5

5x + x2 = -23.5

The x term is 5x.  Take half its coefficient (2.5).

Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.

5x + 6.25 + x2 = -23.5 + 6.25

Reorder the terms:

6.25 + 5x + x2 = -23.5 + 6.25

Combine like terms: -23.5 + 6.25 = -17.25

6.25 + 5x + x2 = -17.25

Factor a perfect square on the left side:

(x + 2.5)(x + 2.5) = -17.25

Can't calculate square root of the right side.

The solution to this equation could not be determined

viktelen [127]3 years ago
4 0

Answer:

x=9

Step-by-step explanation:

-5 square root x =-2+3

5x=4x^2 −12x+9

Simplify  25x-4{x}^{2}+12x-925x−4x 2 +12x−9  to  37x-4{x}^{2}-937x−4x 2-9

then...

(4x−1)(x−9)=0

x=1/4,9

-drop 1/4

x=9

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