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Effectus [21]
3 years ago
9

12.36Un balón lleno contiene 12 kg de oxígeno, O2, bajo una presión ma-nométrica de 40 atm. Determine la masa de oxígeno que se

ha extraído del balón cuando la presión absoluta alcanza el valor de 25 atm. Su-ponga que la temperatura del balón permanece constante. R: 7.3 kg.
Biology
1 answer:
const2013 [10]3 years ago
8 0

Answer:

Quedan 7.317 kilogramos de oxígeno en el balón y se extraen 4.683 kilogramos de oxígeno en el proceso.

Explanation:

Asúmase que el balón es rígido. Supongamos que el oxígeno se comporta como un gas ideal, entonces la ecuación de estado es la siguiente:

P\cdot V = \frac{m\cdot R_{u}\cdot T}{M} (1)

Donde:

P - Presión, medida en atmósferas.

V - Volumen, medido en litros.

m - Masa, medida en kilogramos.

M - Masa molar, medida en kilogramos por kilomol.

T - Temperatura, medida en Kelvin.

R_{u} - Constante de los gases ideales, medida en atmósfera-litros por kilomol-Kelvin.

El aire experimenta un proceso isocórico e isotérmico, entonces obtenemos la siguiente relación:

\frac{P_{1}}{m_{1}} = \frac{P_{2}}{m_{2}} (2)

Nótese que los subíndices 1 y 2 representan los estados inicial y final de proceso.

Si sabemos que P_{1} = 41\,atm, m_{1} = 12\,kg y P_{2} = 25\,atm, entonces la masa final del aire es:

m_{2} = \frac{P_{2}}{P_{1}} \cdot m_{1}

m_{2} = \left(\frac{25\,atm}{41\,atm}\right)\cdot (12\,kg)

m_{2} = 7.317\,kg

La masa que se ha extraído del balón es:

\Delta m = m_{1}-m_{2}

\Delta m = 12\,kg-7.317\,kg

\Delta m = 4.683\,kg

Quedan 7.317 kilogramos de oxígeno en el balón y se extraen 4.683 kilogramos de oxígeno en el proceso.

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