Let f be the function with derivative given by f'(x)=cos(2x^2 -1). How many relative extrema does f have on the interval 2 <
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Answer
given,
352 + 116
we have to break 116 and use it on open number line
breaking of number 116
116 = 100 + 10 + 6
And addition will be shown in the number line attached below
now,
352 + 100 = 452
452 + 10 = 462
462 + 6 = 468
we know
sum of
352 + 116 = 468
