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Dmitry_Shevchenko [17]

3 years ago

9

Philip’s meal costs $12.82 at a local restaurant. The server did their job very well and Philip would like to leave a 20% tip. W

hat amount of money should he leave as a tip?

1 answer:

Elodia [21]3 years ago

8 0

Answer:

$2.56

Step-by-step explanation:

If you multiply 12.82 by .20, you would get 2.564. Then you just round it up and the answer you get is $2.56. Hope this helps!

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PLEASE HELP!! Will give Brainliest!!!

Vesna [10]

Answer:

6.99

Step-by-step explanation:

4.3+1.7=6

41.94/6=6.99

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3 years ago

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PLEASE HELP ANYONE

LUCKY_DIMON [66]

For this problem all you have to do is plug in the value that they is in parenthesis for x. If it says g (x) = x and then it asks g(5) = ?, it is saying what happens if i put 5 in for every x. in this case it would be g (5) = 5. I just replaced x with 5.

So g (-2) we sub -2 for x
g (-2) = -2 (-2)^2 + 3 (-2) - 5
= -2 (4) - 6 - 5
= -19

g (0) = -2 (0) + 3 (0) - 5
= 0 + 0 - t
= -5

g (3) = -2 (3)^2 + 3 (3) - 5
= -18 + 9 - 5
= -14

6 0

3 years ago

A bag contains yellow marbles and blue marbles, 37 in total. The number of yellow marbles is 7 more than 5 times the number of b

Mazyrski [523]

Answer:

32

Step-by-step explanation:

let b represent the number of blue marbles then

yellow = 5b + 7 and

b + 5b + 7 = 37, that is

6b + 7 = 37 ( subtract 7 from both sides )

6b = 30 ( divide both sides by 6 )

b = 5

Thus there are 5 blue and 5(5) + 7 = 25 + 7 = 32 yellow marbles

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3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

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3 years ago

How can i score best mark uee in 2019?

jolli1 [7]

Answer:

You need to study to do good on those exams bud.

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3 years ago

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