Answer:
110 1/4 lb
Step-by-step explanation:
To answer this, multiply 112 1/2 pounds by 49/50:
225 lb 49 11025 lb
---------- * ----- = -------------- = 110 25/100 lb = 110 1/4 lb
2 50 100
Answer:
The answer is nope
Answer:
The correct option is;
B. I and II
Step-by-step explanation:
Statement I: The perpendicular bisectors of ABC intersect at the same point as those of ABE
The above statement is correct because given that ΔABC and ΔABE are inscribed in the circle with center D, their sides are equivalent or similar to tangent lines shifted closer to the circle center such that the perpendicular bisectors of the sides of ΔABC and ΔABE are on the same path as a line joining tangents to the center pf the circle
Which the indicates that the perpendicular the bisectors of the sides of ΔABC and ΔABE will pass through the same point which is the circle center D
Statement II: The distance from C to D is the same as the distance from D to E
The above statement is correct because, D is the center of the circumscribing circle and D and E are points on the circumference such that distance C to D and D to E are both equal to the radial length
Therefore;
The distance from C to D = The distance from D to E = The length of the radius of the circle with center D
Statement III: Bisects CDE
The above statement may be requiring more information
Statement IV The angle bisectors of ABC intersect at the same point as those of ABE
The above statement is incorrect because, the point of intersection of the angle bisectors of ΔABC and ΔABE are the respective in-centers found within the perimeter of ΔABC and ΔABE respectively and are therefore different points.
No because if you were to make 7/3 a mixed fraction, it would be 2 and 1/3. Thus, they are different lengths on the number line
Four options are given for this question, which are: 15/8, 49/64, 56/8 and 21/24.
7/8 = 0.875
15/8 = 1.875
49/64 = 0.7656
56/8 = 7
21/24 = 0.875.
The fraction that has a value that corresponds with that of 7/8 is 21/24, therefore, 21/24 is the correct option.
