30 students only 8 students own only a cat.
.008<.01
The further the number gets from the decimal point, the smaller the number is. The number closest to the decimal point dictates whether the number is bigger or smaller than the other number. For example, .090001 is still greater than .0009999, since the nine is closer to the decimal.
Answer:
B
as [tex]\cos(\theta)=\srqt{1-\sin^2(\theta)}\[tex]
and since theta is in second quadrant, where cosine is negative,
so -√(1-z²)
its .25 my gggggg
Step-by-step explanation:
