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Oksana_A [137]
3 years ago
5

1. Determine the following:

Mathematics
1 answer:
vichka [17]3 years ago
3 0

Answer:

v=d/t

v=340km/85km/h

v=4 km

I hope this helps you

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The table shows the height of a plant as it grows.
viva [34]

Answer

144

Step-by-step explanation:

12*12

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3 years ago
Simplify -4 1/4-(-9 1/2) = ? <br><br>A. -13 1/3 <br>B. -5 1/4<br>C. 13 1/3<br>D. 5 1/4​
bagirrra123 [75]

Answer:

B

Step-by-step explanation:

Hope this helps

5 0
3 years ago
Is the answer B correct?
VashaNatasha [74]
If you do the elimination process, here it is.

- A : Too small

+ B : I think so

- C : I little too big

- D : Way too big
7 0
4 years ago
Read 2 more answers
Which of the following shows a relationship of 4,000 as ten times greater than 400?
stira [4]
400 times ten because when you multiply you get 40,000.
8 0
3 years ago
3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

5 0
3 years ago
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