Answer:
the x² test statistic 13.71
Option a) 13.71 is the correct answer.
Step-by-step explanation:
Given the data in the question;
Feeder                     1      2      3       4
Observed visits;  60   90   92    58
  60   90   92    58
data sample = 300
Expected  = 300 / 4 = 75
 = 300 / 4 = 75
 the x² test statistic = ?
 = ∑[ (
 = ∑[ ( -
 -  )²/
)²/ ]
]
 = [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]
 = [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]
 = [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]
 = [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]
 = 13.7066 ≈ 13.71
 = 13.7066 ≈ 13.71
Therefore, the x² test statistic 13.71
Option a) 13.71 is the correct answer.
 
 
        
             
        
        
        
First you put a 1 under the 2.Then you multiply 85*2 and you get 170.Next you multiply 8.2*1 and you get 8.2.Finally, you divide 170 by 8.2 and get 20.73.
So, your answer to 85/8 times 8.2 = 20.73.
Hope that helped.
        
             
        
        
        
Answer: See the pictures
Step-by-step explanation:
Hope I helped!
Sorry it took so long btw
 
        
             
        
        
        
Answer:
P(success at first attempt) = 0.1353
Step-by-step explanation:
This question follows poisson distribution. Thus, the formula is;
P(k) = (e^(-G) × (G)k)/k! 
where; 
G is number of frames generated in one frame transmission time(or frame slot time)
Let's find G. 
To do this, we need to find number of frames generated in 1 slot time which is given as 50 ms.
Now, in 1000 ms, the number of frames generated = 50
Thus; number of frames generated in 50 ms is;
G = (50/1000) × 50
G = 2.5
To find the chance of success on the first attempt will be given by;
P(success at first attempt) = P(0) = e^(-G) = e^(-2) = 0.1353
 
        
             
        
        
        
The answer is B. y =  0.75 + 2.25. because i've done this assement.