All categories

3 years ago

What is the interest if the principle is $600, the interest rate is 4.5%, and the loan is 5 years?

Mathematics

1 answer:

pogonyaev3 years ago

6 0

Answer:

$135

Step-by-step explanation:

P is the principal amount, $600.00.

r is the interest rate, 4.5% per year, or in decimal form, 4.5/100=0.045.

t is the time involved, 5....year(s) time periods.

So, t is 5....year time periods.

To find the simple interest, we multiply 600 × 0.045 × 5 to get that:

:) hope this helps

You might be interested in

Write the equation that describes each line in slope intercept form

skelet666 [1.2K]

When I did this problem to get slope intercept form I got: Y=-1x+3

4 0

3 years ago

Read 2 more answers

What is the value of x???

lbvjy [14]

cross multiply

20x = 7.4 * 73

x = (7.4 * 73) / 20 = 27.01 answer

5 0

3 years ago

Read 2 more answers

Use milligrams to prove that 1.989•10^27 kilograms are equal to 1.989•10 milligrams.

STatiana [176]

Answer:

I think its 1.784

7 0

3 years ago

A. Find y in terms of x if

givi [52]

Answer:

A. $y(x) =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}$

B.Therefore the solution is defined on the interval:

6≤ x ≤ +∞

Step-by-step explanation:

Given differential equation is

$\frac{dy}{dx} = x^4y^{-1}$

$\Rightarrow \frac{dy}{dx} =\frac{ x^4}{y}$

$\Rightarrow y dy = x^4dx$

Integrating both sides:

$\Rightarrow\int y dy = \int x^4dx$

$\Rightarrow \frac{y^2}{2} =\frac{x^5}{5} +C$ ........(1)

Given y(0)= 6

it means y=0 when x=6

Putting x=6 and y=0 in the equation (1)

$\therefore \frac{0^2}{2} =\frac{6^5}{5} +C$

$\Rightarrow C=-\frac{6^5}{5}$

Equation (1) become:

$\Rightarrow \frac{y^2}{2} =(\frac{x^5}{5} -\frac{6^5}{5})$

$\Rightarrow y} =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}$

Therefore $y(x) =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}$

(B)

The quantity under root must greater than or equal to zero.

Therefore,

$2(\frac{x^5}{5} -\frac{6^5}{5})} \geq0$

$\Rightarrow \frac{x^5}{5} -\frac{6^5}{5}} \geq0$

$\Rightarrow \frac{x^5}{5} \geq\frac{6^5}{5}}$

$\Rightarrow x^5\geq {6^5$

$\Rightarrow \sqrt[5]{x^5} \geq \sqrt[5]{6^5}$

$\Rightarrow x\geq {6$

When x≥0 then the value of $2(\frac{x^5}{5} -\frac{6^5}{5})}$ is real other wise the value of $2(\frac{x^5}{5} -\frac{6^5}{5})}$ is imaginary.

Therefore the solution is defined on the interval:

6≤ x ≤ +∞

8 0

4 years ago

Question in pictures for quadratics

Anika [276]

Sheesh run my branliest boxed like a fish

5 0

3 years ago