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AveGali [126]
3 years ago
6

**due today, please help!!**

Mathematics
2 answers:
marta [7]3 years ago
7 0

Answer:

6(x+2), 3(x+y), 5(2+5x), 3(27x+16), 8(3x+2y+1), 3(1+8x+2y), 9(9x−4y−2), 6(9x+2).

liberstina [14]3 years ago
4 0

Answer:

i got you!

Step-by-step explanation:

6(x + 2)

3(x + y)

5(2x + 5)

3(27x + 16)

8(3x +2y + 1)

3( 1 + 8x +2y)

9( 9x -4y- 2)

6 (9x +2 )

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egoroff_w [7]
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ratelena [41]
Let's consider each of the options; 

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B) It would have to put in the x or y value into the function and check. f(0)=(1/2)^0 

You know that anything to the zero-th power gives 1, therefore, this statement is correct. 

C) Again, if you put in a value such as (1/2)^2, you would be getting a number that is smaller than 1/2, so it isn't always increasing. 

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