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kicyunya [14]
2 years ago
10

-9 - -7 I also need a example for it (try to make the example small the box is not that big) thanks everyone who helps

Mathematics
1 answer:
Sphinxa [80]2 years ago
8 0
It’s positive 2 because if u add or subtract two negative numbers it comes out positive I’m pretty sure
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Value of Pq- qp if p=3 and q = -1?. 1?:)​
aleksklad [387]

Answer:

0 is the answer

7 0
2 years ago
Can you very be kind and answer
Lera25 [3.4K]

area of a circle is PI x r^2

2 = d/2 = 5.4/2 = 2.7 cm

 using 3.14 for PI

3.14 x 2.7^2 = 22.89 square inches

360 degree in a circle, shaded area is 180 degree, which is 50%

 so 22.89 x .5 = 11.45 cm^2

4 0
3 years ago
Answer both please man. Or sorry you'll get a 1 star rating. THanks for answering guys!
Nataliya [291]

For the first one,

x = 10.

For the second one,

x = 12

5 0
3 years ago
Read 2 more answers
¿Cuál de los siguientes puntos no pertenece a la función cuadrática f(x) = 1-x^2 ?
dusya [7]

Answer:

<h2>A. (0,1)</h2>

Step-by-step explanation:

The question lacks the e=required option. Find the complete question below with options.

Which of the following points does not belong to the quadratic function

f(x) = 1-x²?

a.(0,1) b.(1,0) c.(-1,0)

Let f(x) = 0

The equation becomes 1-x² = 0

Solving 1-x² = 0 for x;

subtract 1 from both sides;

1-x²-1 = 0-1

-x² = -1

multiply both sides by minus sign

-(-x²) = -(-1)

x² = 1

take square root of both sides;

√x² = ±√1

x = ±1

x = 1 and x = -1

when x = 1

f(x) = y = 1-1²

y = 1-1

y = 0

when x = -1

f(x) = y = 1-(-1)²

y = 1-1

y = 0

Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)

3 0
3 years ago
Find the value of a and of b for which<br>(a) the solution of x2 + ax &lt; b is<br>-2&lt;x &lt; 4​
KengaRu [80]

Answer: a = -2

b = 8

Step-by-step explanation:

Given :

x^{2} +ax

re - writing the equation , we have

x^{2} +ax-b

we need to find the value of a and b for which -2<x < 4 , this means that the roots of the quadratic equation are -2<x < 4.

The formula for finding the quadratic equation when the roots are known is :

x^{2} - sum of roots(x) + product of root = 0

sum of roots = -2 + 4 = 2

product of roots = -2 x 4 = -8

substituting into the formula , we have:

x^{2} -2x-8=0 , which could be written in inequality form as

x^{2} -2x-8

comparing with x^{2} +ax-b , it means that :

a = -2

b = 8

3 0
2 years ago
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