Answer:
not sure if this is what you mean but you could do 500+49 or 510+39
12x-3-3x=5-(x-8)
9x-3=5-(x-8)
9x-3=5-x+ 8
9x-3=13-x
9x=16- x
10x=16
X= 8/5
90(squared) + 90 (squared) = C (squared)
(we use 90 because the base path is 90 ft long since the diamond is a square that makes all sides 90 ft long)
8100 + 8100 = c(squared)
16200 = c(squared)
we will get the square root of 16200 to get the diagonal length
C=127.3 ft, and since it is the diagonal distance we will device it to 2, to get the distance from the pitcher ro the 2nd base.
127.3/2 = 67.7 ft.
67.7 ft is the distance from the pitcher<span> to the 2nd base.</span>
Answer:
The answer is 4.
Step-by-step explanation:
