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Lynna [10]
2 years ago
5

A pool measuring 8 meters by 28 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the poo

l and the path combined is 468 square​ meters, what is the width of the​ path?
Mathematics
1 answer:
lakkis [162]2 years ago
8 0

Answer: 3 meters'

Step-by-step explanation:

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What is the solution to this inequality?<br>4(2x + 2) + 12 &gt; 100<br>please help!!​
skad [1K]

Subtract 12 from both sides

4(2x + 2) > 100 - 12

Simplify 100 - 12 to 88

4(2x + 2) > 88

Divide both sides by 4

2x + 2 > 88/4

Simplify 88/4 to 22

2x + 2 > 22

Subtract 2 from both sides

2x > 22 - 2

Simplify 22 - 2 to 20

2x > 20

Divide both sides by 2

x > 20/2

Simplify 20/2 to 10

<u>x > 10</u>

7 0
3 years ago
Rewrite 3/100 as the sum of unit fractions
Bingel [31]
1/100+1/100+1/100 Hope this helped! I remember taking this unit in Elementary. Good luck!
6 0
3 years ago
What is the x-intercept of y=40x+70
AysviL [449]
At th x-intercept y=o

∴40x + 70 = 0
  40x = -70
  x = -70/40
  x = -1.75

x intercepr = (-1.75,0)
8 0
3 years ago
A person spends 1/5 of his salary on rent, 3/7 on food, 1/3 on other expenses and saves the rest. If she earns $21,000 per month
sukhopar [10]

Answer:

$9600 saving / year

Step-by-step explanation:

1/5 of $21000 = 21000 / 5 = $4200 / month on rent

3/7 of $21000 = (21000 / 7) x 3 = $9000 / month on food (shocking right :) food is expensive)

1/3 of $21000 = 21000 / 3 = $7000 on other expenses / month

total savings/month = salary/month - rent/month - food/month - other expenses/month

total savings/month = 21000 - 4200 - 9000 - 7000

total savings/month = $800

<u><em>BUT</em></u> the question asks for savings per year. therefore, we must multiply the savings per month by total months per year (12)

800 x 12 = $9600

the person's total savings per year, with a salary of $21000 per month, is equal to $9600 per year

3 0
1 year ago
Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0
2 years ago
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