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4 years ago

A bag contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.

2 answers:

7 0

The simplified probability would be 12/91.

There are 4 green jelly beans out of a total of 14 jelly beans. The probability for the first bean would be 4/14.

Once the first jelly bean is removed, the probability that the second jelly bean would be red is 6/13 (the denominator decreases by 1 because of the first jelly bean that did not get put back).

Together the probability is (4/14)(6/13) = 24/182, which then simplifies to 12/91.

Vanyuwa [196]4 years ago

6 0

Answer:

12/91

Step-by-step explanation:

khan academy

You might be interested in

You collect 140 total pieces of candy trick or treating and 35 of them are m&m's. What fraction of the candy is not m&m'

tekilochka [14]

$\frac{3}{4}$ of the candy is not m&m's.

Step-by-step explanation:

Given,

Total pieces of candy = 140

Number of m&m's = 35

Fraction = $\frac{Number\ of\ m&m}{Total\ pieces\ of\ candy}$

Fraction = $\frac{35}{140}$

Both 35 and 140 are multiples of 7, therefore,

Fraction of m&m's = $\frac{5}{20} = \frac{1}{4}$

As the number of m&m's fraction and not m&m's fraction will make a total of 1, therefore

fraction of m&m's + fraction of not m&m's = 1

fraction of not m&m's = 1 - fraction of m&m's

fraction of not m&m's = $1-\frac{1}{4}=\frac{4-1}{4}$

fraction of not m&m's = $\frac{3}{4}$

$\frac{3}{4}$ of the candy is not m&m's.

Keywords: fraction, subtraction

Learn more about fractions at:

#LearnwithBrainly

7 0

3 years ago

user100 [1]

The answer is 15 I’m pretty sure

6 0

3 years ago

Please help ASAP! Only one question!!

levacccp [35]

It is negative because the plot is going down not up

5 0

3 years ago

A Mexican restaurant sells quesadillas in two sizes: a "large" 10 inch-round quesadilla and a "small" 5 inch-

elena-14-01-66 [18.8K]

Answer:

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^2$

where

r is the radius

step 1

Find the area of the 10 inch-round quesadilla

we have

$D=10\ in$

$r=10/2=5\ in$

substitute

$A=\pi (5)^2$

$A=25\pi\ in^2$

step 2

Find the area of the 5 inch-round quesadilla

we have

$D=5\ in$

$r=5/2=2.5\ in$

substitute

$A=\pi (2.5)^2$

$A=6.25\pi\ in^2$

step 3

Which is larger, half of the 10-inch quesadilla or the entire 5-inch quesadilla?

Compare

half of the 10-inch quesadilla is equal to ----> $\frac{1}{2}(25\pi)=12.5\pi\ in^2$

the entire 5-inch quesadilla ----> $6.25\pi\ in^2$

therefore

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

3 0

3 years ago

How many positive integers under 50 are multiples of neither 4 nor 6

lyudmila [28]

Candidates range from 1 to 50.
50/4=12 positive integers are multiples of 4
50/6=8 positive integers are multiples of 6
50/12=4 positive integers are multiples of 12 (LCM of 4 and 6)
By the inclusion/exclusion principle, the number of multiples of either 4 or 6 is equal to 12+8-4=16.

Therefore, the complement is the number of positive integers that are multiples of neither 4 nor 6 = 50-16=34.

6 0

3 years ago