Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.
Multiply both sides by 100.
Divide both sides by 50.
The amount invested at 7% is 
.
The amount invested at 8% is
The amount invested at 9% is
Therefore, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
x=(-2)
Step-by-step explanation:
subtract 4x from 2x
-6+7=1 4-2=2 subtract 1 from 2
-2x=1 x=-2
Answer:
1300
Step-by-step explanation:
Let the amount put in the station's tank = x
4(400 + x) = 8100 - x Remove the brackets
1600 + 4x = 8100 - x Subtract 1600 from both sides
1600 - 1600 + 4x = 8100 - 1600 - x Do the subtraction
4x = 6500 - x Add x to both sides
4x + x = 6500 - x + x
5x = 6500 Divide by 5
5x/5 = 6500/5
x = 1300
1300 gallons were added to the station's tank.
Answer:
After 2 years Miguel will have in his account $541.64
Step-by-step explanation:
The formula for calculating compound interest continuously is:
Where A is the amount of money obtained after t years.
r is the compound interest rate and p is the initial amount
In this case we have that:
Then we must find the final amount A
Answer:
GURL MY MATH TEACHER GAVE ME THE SAME SHEET A MONTH AGOO
YASS
1.) x is less than or equal to 3
2.) x greater than or equal to 2
3.) x < -1
4.) x greater than or equal to 3
5.) x>2
6.) x greater than or equal to 1
