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NeX [460]
3 years ago
14

-4(y+1)+2 help i am very confused

Mathematics
1 answer:
likoan [24]3 years ago
4 0

Answer:

-4y-2

Step-by-step explanation:

-4(y+1)+2

-4 times y is -4y

-4 times 1 is -4

-4y-4 plus 2

is 4y-2

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There were 578 piglets and 234 adult pigs in the warehouse building yesterday. Today, 126 piglets were sold, and 46 piglets will
natima [27]

Answer:

=406 piglets in the warehouse

Step-by-step explanation:

578-126=452

452-46=406

5 0
2 years ago
I know number 13 is right, how do I do 11 and 12?
snow_tiger [21]
11. 43 ; 137
12. 12 ; 102
8 0
3 years ago
A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest
faltersainse [42]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396

add both amounts, and that's her investment for the 11 years.
7 0
3 years ago
HELPP PLEASE
sasho [114]

Answer:

3 a 20 - class yoga package for 260$

3 0
3 years ago
Anyone want to help me with math
Xelga [282]

Ok, I am ready, what are the questions.

Tell me in the comment section

6 0
3 years ago
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