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3 years ago

In what shape are the lateral faces of a pyramid

Mathematics

1 answer:

Papessa [141]3 years ago

4 0

The shape in which the lateral faces of a pyramid are, are triangles. I hope i helped and my wording made sense. :)

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Rick is buying a t-shirt and a sweater.The sweater costs 3 times as much as the t-shirt.The cost of the sweater is 27$. How much

Sergio039 [100]

Answer:

Step-by-step explanation:

The way you undo multiplication is division. If the sweater costs 27$, you divide that by 3 to get a third of the cost.

6 0

4 years ago

Read 2 more answers

Which point on the graph is the solution to the system of linear equations? -2x=-y+4 x=-2

Elodia [21]

Answer:

The solution is (-2, 0)

Step-by-step explanation:

Re-write -2x=-y+4 x=-2 in column form:

x=-2

-2x=-y+4

Next, substitute -2 for x in the second equation:

-2(-2) = -y + 4, or:

4 = -y + 4. Thus, y must be 0.

The solution is (-2, 0)

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3 years ago

Math help please! Will give 20 points!

sweet-ann [11.9K]

At goal post x= 35
the height will be y= –0.03x2 + 1.6x= 19.25 > 15 
is 4.25 feet above the goal post.

8 0

3 years ago

Your friend calculates the distance between points Q(1,5) and R(3,8), as shown below. What is his error?

borishaifa [10]

The distance between two points is the number of units between them.

The distance between Q and R is 3.61 units

It is impossible to determine your friend's error, because the steps are not given in the question. So, I will calculate the distance between Q and R, instead.

The distance (d) between two points is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

So, the distance QR is:

$QR = \sqrt{(1 - 3)^2 + (5 - 8)^2}$

$QR = \sqrt{(- 2)^2 + (- 3)^2}$

Evaluate exponents

$QR = \sqrt{4 +9}$

$QR = \sqrt{13}$

Take square root of 13

$QR = 3.61$

Hence, the distance between Q and R is 3.61 units