(2x-1)(2x-1)
(4x^2+2x+1)(2x-1)
(2x-1) cancels out so
2x-1
4^2+2x+1
2x^2 - 8x - 24
First, we can factor a 2 out of this expression to simplify it.
2(x^2 - 4x - 12)
Now, we can try factoring this two ways: by using the quadratic formula, or by using the AC method.
We're gonna try using the AC method first.
List factors of -12.
1 * -12
-1 * 12
2 * -6
-2 * 6 (these digits satisfy the criteria.)
Split the middle term.
2(x^2 - 2x + 6x - 12)
Factor by grouping.
2(x(x - 2) + 6(x - 2)
Rearrange terms.
<h3><u>(2)(x + 6)(x - 2) is the fully factored form of the given polynomial.</u></h3>
Answer:
0^6= 1000000. The final answer is 25000000.
Given Information:
Years = t = 35
Semi-annual deposits = P = $2,000
Compounding semi-annually = n = 2
Interest rate = i = 6.5%
Required Information
Accumulated amount = A = ?
Answer:
Accumulated amount = $515,827
Step-by-step explanation:
The future value of amount earned over period of 35 years and interest rate 6.5% with semi-annual deposits is given by
FV = PMT * ((1 + i/n)^nt - 1)/(i/n))
Where
n = 2
i = 0.065
t = 35
FV = 2000*((1 + 0.065/2)^2*35 - 1)/(0.065/2))
FV = 2,000*(257.91)
FV ≈ $515,827
Therefore, Anthony will have an amount of $515,827 when he retires in 35 years.
One for 5.8 and one for 1.2
Hope this helps
