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pashok25 [27]
3 years ago
7

If the ages in a classroom were 11, 12, 12, 13, 13, 14 - what would the median age be if you added someone that was 10 years old

?
Mathematics
1 answer:
Mandarinka [93]3 years ago
5 0

Answer: 12 years old

Step-by-step explanation:

10,11,12,12,13,13,14

The middle in these numbers is 12

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Answer:

390 seniors

Step-by-step explanation:

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2 years ago
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Separate the number 41 and the two parts so that the first number is eight more than twice the second number what are the two nu
vesna_86 [32]

The two numbers are 30 and 11

<em><u>Solution:</u></em>

Given that we have to separate the number 41 into two parts

Let the second number be "x"

<em><u>Given that first number is eight more than twice the second number</u></em>

first number = eight more than twice the second number

first number = 8 + twice the "x"

first number = 8 + 2x

So we can say first number added with second number ends up in 41

first number + second number = 41

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3x = 41 - 8

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x = 11

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7 0
2 years ago
Andy estimated that he would need 79 feet of lumber for a tree house project. He later found that the actual amount of lumber ne
Radda [10]

Answer:

Step-by-step explanation:

79 divided by 68 is your answer

You can do the math

5 0
3 years ago
If m &lt; 0 and b &gt; 0, the graph of y = mx + b does not pass through which quadrant?
stiks02 [169]

Answer:

Quadrant III


Step-by-step explanation:

The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.

The graphs shown are of the functions:

y=-2x+1

y=-3x+3

y=-x+0.5

y=-5x+2


<em>So, any linear function of the form  y=mx+b  with  m  and  b>0  does not pass through Quadrant III. Answer choice 3 is correct.</em>


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3 years ago
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