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3 years ago

7

If the ages in a classroom were 11, 12, 12, 13, 13, 14 - what would the median age be if you added someone that was 10 years old

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1 answer:

Mandarinka [93]3 years ago

5 0

Answer: 12 years old

Step-by-step explanation:

10,11,12,12,13,13,14

The middle in these numbers is 12

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Simplify 2√2-√3<br> ---------------<br> √2+√3

serious [3.7K]

Step-by-step explanation:

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} }$

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} }$

$= \frac{ 2( \sqrt{2} - \sqrt{3} )( \sqrt{2} - \sqrt{3} )}{ { \sqrt{2} }^{2} - { \sqrt{3} }^{2} }$

$= \frac{2(2 - \sqrt{6} - \sqrt{6} - 3) }{2 - 3}$

$= \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}$

$= \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}$

$= 2(1 + 2 \sqrt{6} )$

$= 2 + 4 \sqrt{6}$

6 0

2 years ago

Lori buys a $1500 certificate of deposit (CD) that earns 6% interest that compounds monthly. How much will the CD be worth in:

Studentka2010 [4]

Answer:

$1500

6% interest

use the formula...

P(1+(r/100))^n

where P=initial amount

r=interest rate

t=time period elapsed

so ... for 5 years we get

$1500(1+(6/100))^5 = $1500(1.06)^5 = 2007.3383664

for 10 years

1500(1.06)^10 = 2686.271544814228043264

468 months = 39 years

1500(1.06)^39=14555.261231781943250017719606544

3 0

3 years ago

Read 2 more answers

Which tree diagram shows all of the possible outcomes for tossing a coin and rolling a fair number pyramid that

pshichka [43]

Answer:

D : This is because there are 8 outcomes and 2 events.

It cannot be C as C does not show true event outcomes on each H or T event.

Step-by-step explanation:

3 0

3 years ago

The height of Josie's dog is 11 1/4 inches to the nearest quarter inch and 11 inches to the nearest half inch. Which measurement

goldenfox [79]

Dear Kellyeasterday, 11 1/4 inches is more precise.

5 0

3 years ago

Can someone please help me ASAP

deff fn [24]

Answer:

QR = 17 cm

Step-by-step explanation:

Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then

TS = 5 cm and PT = 2 × 5 = 10 cm

So PS = 10 + 5 = 15 cm

PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm

Using the right triangle formed calculate QR using Pythagoras' identity

QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )

QR = $\sqrt{289}$ = 17

3 0

3 years ago