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Lady_Fox [76]
3 years ago
11

Billy Anderson is choosing between two fitness centers. Center A charges $395 per year for unlimited use of all facilities. Cent

er B charges a $25 sign up fee, a $15 monthly fee, and $5 per aerobics class. If Billy goes to aerobics once a week, which club is least expensive for him to use for a year?
which facility is cheaper?
Mathematics
2 answers:
weeeeeb [17]3 years ago
8 0
Center A = $395 for the year
Center B = 25 + 12(15) + 52(5) = $465.

Center A is cheaper.
kati45 [8]3 years ago
3 0
Okay. We know that Center A charges $395 for an entire year. For Center B, there is a $25 sign up fee to pay one time, and then there is $15 monthly fee and $5 per aerobics class. There are 12 months in 1 year and 15 * 12 = 180. There are 52 weeks in 1 year, so 5 * 52 is 260. 260 + 180 + 25 = 465. He would pay $465 a year at Center B. Based off of the numbers, if Billy were to use a facility for only a year and go to aerobics once a week, then Center A is definitely cheaper than Center B. 
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Homework
Zolol [24]

<u><em>Note:</em></u><em> As you have missed to mention the first four terms of the Arithmetic sequence. So, I am randomly assuming that first four terms of the arithmetic sequence be 1, 3, 5, 7... This would anyhow make you understand the concept. So, I am solving your query based on assuming the first four terms of an Arithmetic sequence as 1, 3, 5, 7...</em>

Part A)

<em><u>What is the next term of this sequence?</u></em>

Answer:

{\displaystyle \ a_{5}=9 is the next term i.e. 5th term of the arithmetic sequence <em>1, 3, 5, 7...</em>

Step-by-step explanation:

Considering the Arithmetic sequence with fist four terms

<em> 1, 3, 5, 7...</em>

As we know that a sequence is termed as arithmetic sequence of numbers if the difference of any two consecutive terms of the sequence remains constant.

For instance, <em> 1, 3, 5, 7... </em>will be an arithmetic sequence having the common difference 2. Common difference is denoted by 'd'.

So,

Given the sequence

<em>1, 3, 5, 7...</em>

d=3-1=2,d=5-3=2

As a_{1} = 1 and d = 2

The next term i.e. 5th term can be found by using the nth term of the sequence.

So, consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Putting n=5 in, a_{1} = 1 and d = 2  in {\displaystyle \ a_{n}=a_{1}+(n-1)d} to find the 5th term.

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

{\displaystyle \ a_{5}=1+(5-1)2}

{\displaystyle \ a_{5}=1+(4)2}

{\displaystyle \ a_{5}=9

So, {\displaystyle \ a_{5}=9 is the next term i.e. 5th term of the arithmetic sequence <em>1, 3, 5, 7...</em>

Part B)

<u><em>Writing down an expression,  in terms of n for the nth term of the sequence</em></u>

consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Here, a_{1} is the first term, d is the common difference.

For example,

Given the sequence

<em>1, 3, 5, 7...</em>

d=3-1=2,d=5-3=2

As a_{1} = 1 and d = 2

The next term i.e. 5th term can be found by using the nth term of the sequence.

So, consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Putting n=5 in, a_{1} = 1 and d = 2  in {\displaystyle \ a_{n}=a_{1}+(n-1)d} to find the 5th term.

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

{\displaystyle \ a_{5}=1+(5-1)2}

{\displaystyle \ a_{5}=1+(4)2}

{\displaystyle \ a_{5}=9

Keywords: arithmetic sequence, nth term, common difference

Learn more abut arithmetic sequence, nth term and common difference from brainly.com/question/12227567

#learnwithBrainly

7 0
4 years ago
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