Question

1/3(6x+24)-20 < -1/2(6x-36)

Answer 1

Hi there!
The question here gives us an inequality, and it tells us to solve for x. 
$\frac{1}{3} (6x+24)-20 \ \textless \ - \frac{1}{2} (6x-36)$
First, use the distributive property to simplify both sides of the equation.
$2x+8-20\ \textless \ -3x+18$
Now, on the left side of the inequality, combine like terms.
$2x-12\ \textless \ -3x+18$
Add 12 to both sides.
$2x\ \textless \ -3x+30$
Add 3x to both sides.
$5x\ \textless \ 30$
Divide 5 from both sides.
$x\ \textless \ 6$
Therefore, the solution to the inequality is anything less than 6, or x < 6. Hope this helped!