<u>Given that </u>–
<u>We know that</u> –
Then –
Now the number of moles of KOH need to ensure that concentration of Hydroxide anions is equal to –
Volume of the solution contains the need number of moles of Hydroxide anions –
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N(CaCO3)=m÷M
m being the mass of the sample and M being the molar mass of the compound; Molar mass is to be obtained by adding the atomic masses of all the elements in the compound.
therefore,
n(CaCO3)=m÷M
=28g÷100 g.mol
=0.28 mol
therefore, there are 0.28 moles in 28g of Calcium Carbonate.
<u>Answer:</u> The moles of carbon dioxide formed in the reaction is 20 moles.
<u>Explanation:</u>
We are given:
Number of moles of butane = 5.0 moles
The chemical reaction for the combustion of butane follows the equation:
As, oxygen is present in excess. So, it is considered as an excess reagent.
Thus, butane is considered as a limiting reagent because it limits the formation of products.
By stoichiometry of the reaction:
2 moles of butane produces 8 moles of carbon dioxide.
So, 5 moles of butane will produce = of carbon dioxide.
Hence, the moles of carbon dioxide formed in the reaction is 20 moles.
<h3>
Answer:</h3>
61.3 mL
<h3>
Explanation:</h3>
From the data given;
- Mass of volumetric flask is 109.1 g
- Mass of salt is 5.01 g
- Mass of Volumetric flask and salt is 113.5 g
- Mass of volumetric flask and salt solution is 170.4 g
- Mass of salt solution is 61.3 g
We are required to calculate the volume of salt solution;
We need to know the relationship between density, mass and volume of a solution.
Density = Mass ÷ Volume
Therefore, given mass and density we can find the volume.
Rearranging the formula;
Volume = Mass ÷ density
Assuming the density of salt solution is 1 g/mL
Then;
Volume = Mass of the salt solution ÷ density of the salt solution
= 61.3 g ÷ 1 g/mL
= 61.3 mL
Therefore, the volume of the salt solution is 61.3 mL
Answer: Do you take Ms. Reyes
Explanation: The answer is Outside air, Nose, Lungs, Bloodstream, Cell