Answer : The mass of excess reactant will be left over is 4.03 g and mass of
is 34.2 g.
Solution : Given,
Mass of Cu = 9.85 g
Mass of
= 31.0 g
Molar mass of Cu = 64 g/mole
Molar mass of
= 170 g/mole
Molar mass of
= 188 g/mole
First we have to calculate the moles of Cu and
.


Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,

From the balanced reaction we conclude that
As, 2 mole of
react with 1 mole of 
So, 0.182 moles of
react with
moles of 
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Moles of remaining excess reactant = 0.154 - 0.091 = 0.063 moles
Now we have to calculate the mass of excess reactant will be left over.


Now we have to calculate the moles of 
From the reaction, we conclude that
As, 2 mole of
react to give 1 mole of 
So, 0.182 moles of
react to give
moles of 
Now we have to calculate the mass of 


Therefore, the mass of
is 34.2 grams.