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4 years ago

7

Help....plzzzzzzzzzzzzz

1 answer:

Marianna [84]4 years ago

3 0

Could you put down the question and answers?

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Which is the correct answer

VashaNatasha [74]

Let s denote the number of pages in each issue of the sports magazine.

Let t denote the number of pages in each issue of the technology magazine.

Given that a sports magazine prints 12 issues per year and a technology magazine prints 10 issues per year.The total number of pages in all the issues of the sports magazine for one year is 32 more than the total number of pages in all the issues of the technology magazine for one year.

This can be written in equation as,

$12s=10t+32$

Since, it is given that, "Each issue of the sports magazine has 18 fewer pages than each issue of the technology magazine".

This can be written in equation as,

$s=t-18$

Thus, the set of equations that represent the given data is

$12s=10t+32$ and $s=t-18$

Hence, Option A is the correct answer.

7 0

4 years ago

Part A: Rhett made $250 washing cars with his mobile car wash company. He charges $70 per car and earned $50 in tips. Write an e

Natasha2012 [34]

Answer:

250=70x+50

Step-by-step explanation:

5 0

3 years ago

Can you help with this please!! Thank you

user100 [1]

Answer:

20

your welcome

Step-by-step explanation:

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8 0

4 years ago

Suppose a random variable, x, arises from a binomial experiment. If n = 6, and p = 0.30, find the following probabilities using

AlladinOne [14]

Answer:

<u></u>

<u>a) P(X=1) = 0.302526</u>

<u>b) P(X=5) = 0.010206</u>

<u>c) P(X=3) = 0.18522</u>

<u>d) P(X≤3) = 0.92953</u>

<u>e) P(X≥5) = 0.010935</u>

<u>f) P(X≤4) = 0.989065</u>

Explanation:

Binomial experiments are modeled by the formula:

$P(X=x)=C(n,x)\cdot p^x\cdot (1-p)^{(n-x)}$

Where

P(X=x) is the probability of exactly x successes

$C(n,x)=\dfrac{n!}{x!\cdot (n-x)!}$

p is the probability of one success, which must be the same for every trial, and every trial must be independent of other trial.

n is the number of trials

1 - p is the probability of fail

there are only two possible outcomes for each trial: success or fail.

<u>a.) P (x=1)</u>

<u></u>

$P(X=1)=\dfrac{6!}{1!\cdot (6-1)!}\times (0.3)^1\times(1-0.3)^{(6-1)}=0.302526$

<u>b.) P (x=5)</u>

$P(X=5)=\dfrac{5!}{5!\cdot (6-5)!}\times (0.3)^5\times (1-0.3)^{(6-5)}=0.010206$

<u>c.) P (x=3)</u>

Using the same formula:

$P(X=3)=0.18522$

<u>d.) P (x less than or equal to 3)</u>

P(X≤3)= P(X=3) + P(X=2) + P(X=1) + P(X=0)

Also,

P(X≤3) = 1 - P(X≥4) = 1 - P(X=4) - P(X=5) - P(X=6)

You can use either of those approaches. The result is the same.

Using the second one:

P(X=4) = 0.059335
P(X=5) = 0.010206
P(X=6) = 0.000729

P(X≤3) = 1 - 0.05935 - 0.010206 - 0.000729 = 0.92953

<u>e.) P(x greather than or equal to 5)</u>

P(X≥5) = P(X=5) + P(X=6)

P(X≥5) = 0.010206 + 0.000729 = 0.010935

<u>f.) P(x less than or equal 4)</u>

P(X≤4) = 1 - P(X≥5) = 1 - P(X=5) - P(X=6)

P(X≤4) = 1 - 0.010206 - 0.000729 = 0.989065

5 0

4 years ago

Write the sum using summation notation, assuming the suggested pattern continues.

Lina20 [59]

<u>ANSWER</u>

$\sum _{n = 1} ^{18} (6n - 15)$

<u>EXPLANATION</u>

The given series

$- 9 - 3 + 3 + 9 + ... + 81$

This is an arithmetic series with a common difference of

$d = - 3 - - 9 = 6$

The first term of the series is:

$a_1 = - 9$

The general term is given by:

$a_n =a_1 + d(n - 1)$

$a_n = - 9+ 6(n - 1)$

$a_n = - 9+ 6n - 6$

$a_n =6n - 15$

The last term is 81

We can use this to determine the number of terms in the series.

$81=6n - 15$

$81 + 15=6n$

$6n = 96$

$n = \frac{96}{6} = 16$

The summation notation is:

$\sum _{n = 1} ^{18} (6n - 15)$

4 0

3 years ago