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Mrac [35]
3 years ago
13

What is (-3)-(-6)×(-9)?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
3 0
(-3)-(-6)×(-9)

Simplify your equation to make it look neater.

(-3)+(6)×(-9)

Combine like terms.

(-3+6)×(-9)

Simplify.

(3)×(-9)

Simplify. Remember, a negative times a positive is ALWAYS a negative. 

-27

~Hope I helped!~




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Match the steps to find the equation of the parabola with focus (-1, 2) and directrix x = 5.
Archy [21]

Answer:

The matched options to the given problem is below:

Step1: Choose a point on the parabola

Step2: Find the distance from the focus to the point on the parabola.

Step3: Use (x, y).

Find the distance from the point on the parabola to the directrix.

Step4: Set the distance from focus to the point equal to the distance from directrix to the point.

Step5: Square both sides and simplify.

Step6: Write the equation of the parabola.

Step by step Explanation:

Given that the focus (-1,2) and directrix x=5

To find the equation of the parabola:

By using focus directrix property of parabola

Let S be a point and d be line

focus (-1,2) and directrix x=5 respectively

If P is any point on the parabola then p is equidistants from S and d

Focus S=(-1,2), d:x-5=0

Step1: Let P(x,y) be any point on parabola

Step2: Therefore the d=\sqrt{(x+1)^2+(y-2)^2}\hfill (1)

Step3: The perpendicular distance from p to d is

\frac{|x-5|}{\sqrt{(-1)^2+2^2}}

=\frac{|x-5|}{\sqrt{5}}\hfill (2)

Step4: equating (1) and (2)

\sqrt{(x+1)^2+(y-2)^2}=\frac{|x-5|}{\sqrt{5}}

Step5: squaring on both sides

(x+1)^2+(y-2)^2=\frac{|x-5|^2}{5}

5[(x+1)^2+(y-2)^2]=(x-5)^2

5[x^2+2x+1+y^2-2y+4-x^2+10x-25]=0

12x+y^2-2y-24=0

Step6: Equation of the parabola is

y^2-2y+12x-24=0

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3 years ago
Combining like terms ,algebra
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14x + 7 + 4 = 14x + 11

9x - 3 - 7x + 4 = 2x + 1

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Answer:

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The equation for the driver's average speed s during the acceleration will be:

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