Let the number of gallons consumed be the first car be x, and that of the second car, y. Then:
x + y = 50 . . . . . . . (1)
20x + 15y = 850. . . (2)
(1) x 20 => 20x + 20y = 1000 . . . (3)
(2) - (3) => -5y = -150 => y = -150/-5 = 30
From (1), x + 30 = 50 => x = 50 - 30 = 20
Therefore, first car consumed 20 gallons and the second consumed 30 gallons.
To find the percent you would divide 591 by 2364
591/2364=.25
.25*100 = 25%
Does that make sense?
You divide 56.28 by 3 so 18.76 then multiply by 7 which is 131.32 hope this helps!
Let “t” represent the number of minutes Martha exercises each day. If she needs to exercise *at least* 30 minutes, t has to be equal to or greater than 30, so our inequality would be
t ≥ 30
Yes they are the same because when the negative is distributed into (an+c), the plus sign becomes a negative.
