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agasfer [191]
3 years ago
7

Tell whether the triangle with the given side lengths is a right triangle.

Mathematics
1 answer:
Ulleksa [173]3 years ago
7 0

Answer:

Monkey says NO

Step-by-step explanation:

Monkey says A^2 + B^2 = C^2. Monkey do math, gets C = 8.5. So close, monkey sad. Not right triangle.

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Ten out of every 32 people
gogolik [260]

Answer:

5%

Step-by-step explanation:

3 0
3 years ago
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An oil drilling company ventures into various locations, and its success or failure is independent from one location to another.
densk [106]

Answer:

a) 18.77% probability that the driller drills at 10 locations and has 1 success

b) 75.60% probability that the driller drills at 10 locations and has at least 2 success

Step-by-step explanation:

For each drill, there are only two possible outcomes. Either it is a success, or it is not. The probability of a drill being a success is independent of other drills. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

10 locations

This means that n = 10

Suppose the probability of a success at any specific location is 0.25.

This means that p = 0.25

(a) What is the probability that the driller drills at 10 locations and has 1 success?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.25)^{1}.(0.75)^{9} = 0.1877

18.77% probability that the driller drills at 10 locations and has 1 success

(b) What is the probability that the driller drills at 10 locations and has at least 2 success?

Either there are less than 2 success, or there are at least 2. The sum of the probabilities of these events is decimal 1. So

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.25)^{0}.(0.75)^{10} = 0.0563

P(X = 1) = C_{10,1}.(0.25)^{1}.(0.75)^{9} = 0.1877

P(X < 2) = P(X = 0) + P(X = 1) = 0.0563 + 0.1877 = 0.2440

P(X < 2) = P(X = 0) + P(X = 1) = 1 - 0.244 = 0.756

75.60% probability that the driller drills at 10 locations and has at least 2 success

8 0
3 years ago
Answer this maths question: x³+y³+z³
True [87]

Answer:

(x+y+z)^3

Step-by-step explanation:

5 0
3 years ago
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MrRissso [65]

Answer:

the first and last one

Step-by-step explanation:

3*3*3/3*3*3*3*3

3^3

3 0
3 years ago
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For a given geometric sequence, the 9th term, a9, is equal to 43/256 and the 14th term, a14, is equal to 172. Find the value of
NeX [460]
Maybe solve by dividing. I think 5/6. Sorry math isn’t my strong suit. I’m good at reading.
5 0
3 years ago
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